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Various congruences involving binomial coefficients and higher-order Catalan numbers

Journal article published in 2009 by Zhi-Wei Sun
This paper is available in a repository.
This paper is available in a repository.

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Abstract

Let $p$ be a prime and let $a$ be a positive integer. In this paper we investigate $∑_{k=0}^{p^a-1}\binom[(h+1)k,k+d]/m^k$ modulo a prime $p$, where $d$ and $m$ are integers with $-h<d<=p^a$ and $m\not=0 (mod p)$. We also study congruences involving higher-order Catalan numbers $C_k^{(h)}=\binom[(h+1)k,k]/(hk+1)$ and $\bar C_k^{(h)}=\binomal[(h+1)k,k]*h/(k+1)$. Our tools include linear recurrences and the theory of cubic residues. Here are some typical results in the paper. (i) If $p^a=1 (mod 6)$ then $∑_{k=1}^{p^a-1}\binom[3k,k]/6^k=2^{(p^a-1)/3}-1 (mod p).$ Also, $∑_{k=0}^{p^a-1}\binom[3k,k]/7^k=\cases-2&if p^a=±2 (mod 7), \\1&otherwise.$ (ii) We have $∑_{k=1}^{p^a-1}\binom[4k,k]/5^k=\cases1 (mod p) if p\not=11 and p^a=1 (mod 5), \1/11 (mod p)&if p^a=2,3 (mod 5), \9/11 (mod p) if p^a=4 (mod 5). $ Also, $∑_{k=0}^{p^a-1}C_k^{(3)}/5^k=\cases1 (mod p) if p^a=1,3 (mod 5), \2 (mod p) if p^a=2 (mod 5), \\0 (mod p)& p^a=4 (mod 5).$ Comment: 33 pages. Extended version